Search found 2 matches

by Jannis636
24 Oct 2018 13:28
Forum: User Help / Bug Reports
Topic: replace " " with %
Replies: 2
Views: 6220

Re: replace " " with %

I solved it with
replaceAll(someText, "\\s", "%")
by Jannis636
23 Oct 2018 11:14
Forum: User Help / Bug Reports
Topic: replace " " with %
Replies: 2
Views: 6220

replace " " with %

Why i can not replace an empty string (" ") with another charactor? stringName =replace(stringName, " ", "%"); does not work?!