extract adresse from google map ?

[joeko]

hmm, all fine now but how i create a new variable with blank space between road and house_number ?

address = (road) + (house_number);

result is street1 and not street 1

[Desmanto]

If you check the result of the json in debug dialog, then choose to show it in json view, you will see something like this.

Code: Select all

[{
  "place_id": 79652320,
  "licence": "Data © OpenStreetMap contributors, ODbL 1.0. https://osm.org/copyright",
  "osm_type": "way",
  "osm_id": 23384770,
  "boundingbox": [
    "53.5868484",
    "53.5878464",
    "10.0977657",
    "10.099514"
  ],
  "lat": "53.58736045",
  "lon": "10.0985517127999",
  "display_name": "toom Baumarkt, 31,33, Am Stadtrand, Wandsbek, Hinschenfelde, Hamburg, 22047, Deutschland",
  "class": "shop",
  "type": "doityourself",
  "importance": 0.21100000000000002,
  "icon": "https://nominatim.openstreetmap.org/images/mapicons/shopping_diy.p.20.png",
  "address": {
    "doityourself": "toom Baumarkt",
    "house_number": "31,33",
    "road": "Am Stadtrand",
    "suburb": "Wandsbek",
    "city_district": "Wandsbek",
    "hamlet": "Hinschenfelde",
    "state": "Hamburg",
    "postcode": "22047",
    "country": "Deutschland",
    "country_code": "de"
  }
}]

It is easier to know the hierarchy now. So if we parse it now, it becomes

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road = js[0]["address"]["road"];
house_number = js[0]["address"]["house_number"];
city_district = js[0]["address"]["city_district"];

Then if we want to add some space, you can add string with space in between, or just use inline variable.

Code: Select all

address = road + " " + house_number + ", " + city_district ;
address = "{road} {house_number}, {city_district}";

Both give the same result, Am Stadtrand 31,33, Wandsbek
I prefer the + method when the variable is not final, I might append something later, or just for the purpose to see the variable easier.
I prefer the inline method when the variable is final, the address is ready to be shown in some display (example toast message or notification). Because using inline variable, makes it a bit difficult to spot the variable now, as the coloring is green and inside string.