Automagic Forum

I have an initial value 0. Then everytime a flow triggers, it add 1 to value: value = value + 1

Then I test the value in expression: value == 2 * n
True path should execute everytime the value is 0, 2, 4, 6, 8, etc...

Ideally I need an universal solution for n, so that the same solution could be used for example in x^n, x+n, x/n, and so on.

Math is one thing where my english is not good, so I can't really explain my question well. Try to bear with me...

Hi Murtuma,

I don't think you'll be able to get a generic solution for all the problems you listed. I'm also not quite sure I understood the problem, so I'll try to list a couple of tips:

> True path should execute everytime the value is 0, 2, 4, 6, 8, etc...
This one is simple: use the modulo operator. Modulo is the remainder of a division. So for example 6 modulo 2 is 0 (6 divided by 2 is 3 with 0 remainder) while 7 modulo 2 is 1 (7 divided by 2 is 3 with 1 remaining). So you could write an expression "value % 2 == 0" to get what you wanted. Or use "value % 3 == 0" for "0, 3, 6, 9, ...".

> Ideally I need an universal solution for n, so that the same solution could be used for example in x^n, x+n, x/n, and so on.
I don't know what your "x" is supposed to be, so I can't really relate to the problem.

Cheers
Loris

lchiocca wrote:> Ideally I need an universal solution for n, so that the same solution could be used for example in x^n, x+n, x/n, and so on.
I don't know what your "x" is supposed to be, so I can't really relate to the problem.

Yeah, those examples didn't really support my explanation well.

I'll try again.

Expression: value == 2 * n
n is indefinited variable, so every time value is multiplied by *any number*, expression would return TRUE.

As it seems, there's not such function(indefinite variable), could you add this function to AM scripting language?

Isn't the modulo what you are looking for? (see my first post)

How about value = 2*0. ... 0 is also an "any number", and in your example, no matter what 2 is multiplied with, it will always be multiplied by a number.

Or is it merely determining whether the result of your multiplication is even or odd you're after?

This doesn't quite match the description in your initial post, where you multiply n by two, then test whether the result is a multiple of two - answer to that is simple: that will always be the case.

Maybe you can try to explain in which circumstances you want the result NOT to be true?